Something to let you guys to think about it. It's nice to let your brain to work once in a while.
You are given RM100 and asked to buy some chickens, hens and cocks.
The price for each
Cock = RM6
Hen = RM3
Chicken = RM0.10
The only catch is you have to spend exactly RM100 to buy exactly 100 units of the combined chickens, hens and cocks. What is the correct combination?
The price for each
Cock = RM6
Hen = RM3
Chicken = RM0.10
The only catch is you have to spend exactly RM100 to buy exactly 100 units of the combined chickens, hens and cocks. What is the correct combination?
p/s: Will reveal the answer in my next post.
3 comments:
haha...Long time never do maths liao..so let me solve in strict mathematical way..
Let, Cock = x
Hen = y
Chicken = z
So, RM6x + RM3y + RM0.10z = RM100
Which gives us,
6x + 3y + 0.1z = 100 ---> (1)
For 100 unit,
x + y + z = 100
Rearrange,
z = 100 - x - y ---> (2)
Replace (2) into (1),
6x + 3y + 0.1(100 - x - y) = 100
5.9x + 2.9y = 90
By trial & error,
We get,
x = 1
y = 29
Hence, 1 + 29 + z = 100
z = 70
The result,
RM6(1) + RM3(29) + RM0.10(70) = RM100
and,
1 + 29 + 70 = 100
Therefore
Cock = 1
Hen = 29
Chicken = 70
So, what's the prize??
i'll buy 100 chickens at rm0.10 per chick. that would be rm10.00.
the balance rm90.00 i'll buy lisan & myself kfc for the next 1 week :)
Paullie: Yes bingo! Well done! The prize will be KFC from Mich.
Mich: You don't mind paying for Paullie also right? :)
Post a Comment