Sunday, October 01, 2006

Riddle of the day

Something to let you guys to think about it. It's nice to let your brain to work once in a while.
You are given RM100 and asked to buy some chickens, hens and cocks.

The price for each
Cock = RM6
Hen = RM3
Chicken = RM0.10

The only catch is you have to spend exactly RM100 to buy exactly 100 units of the combined chickens, hens and cocks. What is the correct combination?
p/s: Will reveal the answer in my next post.

3 comments:

Survon said...

haha...Long time never do maths liao..so let me solve in strict mathematical way..

Let, Cock = x
Hen = y
Chicken = z

So, RM6x + RM3y + RM0.10z = RM100
Which gives us,
6x + 3y + 0.1z = 100 ---> (1)

For 100 unit,
x + y + z = 100
Rearrange,
z = 100 - x - y ---> (2)

Replace (2) into (1),
6x + 3y + 0.1(100 - x - y) = 100
5.9x + 2.9y = 90

By trial & error,
We get,
x = 1
y = 29

Hence, 1 + 29 + z = 100
z = 70

The result,
RM6(1) + RM3(29) + RM0.10(70) = RM100
and,
1 + 29 + 70 = 100

Therefore
Cock = 1
Hen = 29
Chicken = 70

So, what's the prize??

michelle said...

i'll buy 100 chickens at rm0.10 per chick. that would be rm10.00.

the balance rm90.00 i'll buy lisan & myself kfc for the next 1 week :)

Lisan said...

Paullie: Yes bingo! Well done! The prize will be KFC from Mich.

Mich: You don't mind paying for Paullie also right? :)